Problem 4Draw
the schematic of a 2-input CMOS NAND gate and explain its working.
Answer:
The circuit
is given below:

Its working can
be explained as follows:
- If A is low,
Q1 is on and Q2 is off. The output is high, regardless of the state
of B.
- If B is low,
Q4 is on and Q3 is off. The output is high, regardless of the state
of A.
- If A and B
are both high, then Q1 and Q4 are both off and Q2 and Q3 are both
on. The output is low.
This can be summarised
by the following truth table:
| A |
B |
X |
| 0 |
0 |
1 |
| 0 |
1 |
1 |
| 1 |
0 |
1 |
| 1 |
1 |
0 |
Contributor:
Naveen PN
8-01
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