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by Ernesto
Gradin & Aubrey Kagan
Start ý Features
ý Magnetics ý Primary
and Secondary Turns ý Primary and Secondary
Winding ý Primary Inductance ý Hardware
ý Firmware ý Analog
to Digital Conversion ý User Interface
ý Sources and PDF
MAGNETICS
Figure 2 shows the equivalent circuit
of the current generating transformer. The output current from the
power amplifier has three components of three different phases. IL
is the current through the inductive component, IR is the
current through the reflected resistive component (from the secondary),
and IC is the current through the capacitance of the circuit.
A capacitor can be added to cancel the current required by the inductive
component, reducing the current drive requirements of the amplifier.
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| Figure 2ýNo real electrical
component is ideal. The imperfections, as well as impedances
reflected from one side of the transformer to the other, are
shown in an equivalent circuit. Also indicated is the way the
total current splits to pass through individual components. |
The internal resistance of the secondary
(RI) is made up of wire resistance, plus the transferred
impedance of the primary, plus the resistance of the measurement shunt
and the transferred impedance from the secondary of the current measuring
transformer. RL is the load in the unit under test.
ESTABLISH CONSTANTS
To design the transformer, you must introduce
values from the actual circuitry that you are going to use. For example,
we decided to generate a 10-A output AC current. The load (RL)
is 25 milliohms (a shunt internal to the product), and the wiring
resistance of the secondary, so Ri is assumed to be 25
milliohms as well.
In addition, a transformer core must
be selected. We had several spare toroidal transformers that we disassembled.
The measurements of the transformer core were as follows:
ý Cross-sectional height, H = 2.15 cm
ý Cross-sectional width, W = 1.60 cm
ý Inner diameter, D = 3.93 cm
Prior to the other calculations, the
inductance per turn (LT) must also be known. This can be
calculated from the magnetic constants if the core data is available,
as shown as follows:

where S is the core cross-sectional
area in square centimeters, Cm is the mean circumference
of the toroid (2 ý p ý (outside
diameterýinside diameter)), and N is the total number of turns.
m eff is
the effective permeability of the material. In a toroid, this is essentially
the permeability of the material. Once L has been calculated
from the above formula, LT can be calculated as:

Prior to the other calculations, the
inductance per turn (LT) must also be known. This can be
calculated from the magnetic constants if the core data is available,
as shown above. Alternatively, it can be measured with an LCR bridge.
Winding five turns through the core and measuring the inductance gave
40.7 ýH. The inductance is proportional to the square of the number
of turns. Therefore, LT is calculated as 40.7/52
= 1.63 ýH/turn2.
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ýCircuit Cellar, the Magazine for Computer Applications. Posted with
permission. |