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by George Novacek
Start ý Nonlinear
Loads ý Harmonic Distortion ý Power
Factor Correction ý Sources and PDF
NONLINEAR LOADS
Letýs consider a simple, hypothetical
situation. Say you need a power supply to deliver 12 VDC to a 100-ohm
load, that is a 120-mA current with a reasonably low (<1%) ripple.
Nothing could be simpler, right? The schematic diagram of the rectifier
is shown in Figure 1. And, the voltage across the load and its ripple
are plotted in Figure 2. Thatýs exactly what you need, so whereýs
the problem?
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| Figure 1ýThis simple, full-wave
rectifier delivers 12 V at 120 mA to a 100-ohm load. |
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| Figure 2ýThe DC ripple satisfies
your requirement. The ripple is less than 1%. |
Take a look at Figure 3, which is the
time domain plot of the input AC voltage and current. The voltage
(shown in blue trace) is a nice 60-Hz sine wave. The current (shown
by the red trace) does not resemble a sinusoidal wave even with a
great deal of imagination. It is distorted beyond recognition, and
one of the results is immediately obivious when you look at the current
axis. With the AC input voltage approximately 9-V rms, the input current
should be roughly 150-mA rms, or 210-mA peak. Instead, the current
reaches almost 900-mA peak, which is more than four times as much.
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| Figure 3ýThe rectifier is a
nonlinear load. With the input voltage perfectly sinusoidal,
the current resembles a train of pulses. |
This may not be a big deal when building
a home project, but if youýre working for a power company supplying
power to zillions of such devices, with all the current peaks synchronized
to the same sine wave, it is a serious problem. Imagine that you are
responsible for the design of a vehicle power distribution system
where the power is generated (as usual) by an AC alternator. The vehicle
has a number of servo systems with DC motor actuators, each equipped
with appropriate rectifiers. All of these actuators may be functioning
at the same time. And now, because of the nonlinear distortion that
the rectifiers cause, your generator and wiring may have to be rated
for several times the power the system actually needs. You add cost
and weight and the efficiency will be terrible, thereby wasting fuel.
By observing the waveforms on the oscilloscope
you can easily tell that they are distorted, but how do you quantify
them? For that you must consider the waveform in the frequency domain
as opposed to the time domain (as seen on a scope) by performing a
Fourier analysis.
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ýCircuit Cellar, the Magazine for Computer Applications. Posted with
permission. |