ChipCenter Questlink
SEARCH CHIPCENTER
Search Type:
Search for:




Knowledge Centers
Product Reviews
Data Sheets
Guides & Experts
News
International
Ask Us
Circuit Cellar Online
App Notes
NetSeminars
Careers
Resources
FAQ
EE Times Network
Electronics Group Sites

Answer1


Circuit Cellar Online
THE MAGAZINE FOR COMPUTER APPLICATIONS
Circuit Cellar Online offers articles illustrating creative solutions
and unique applications through complete projects, practical
tutorials, and useful design techniques.

Archive

WHAT'S YOUR ENGINEERING QUOTIENT?

Test Your EQ

Problem 6A zener diode in the circuit shown in the figure has a knee current of 5mA, and a maximum allowed power dissipation of 300mW. What are the minimum and maximum currents that can be drawn safely by the load, keeping the output voltage Vo constant at 6V?

 


Answer 6

The current through the 50-ohm resistor is fixed at I = (9 ý 6 V) / 50 ohms = 60 mA.

The maximum current through the zener is 300 mW / 6 V = 50 mA.

Therefore, the minimum current through load (when the zener is drawing the maximum current) is 60 mA ý 50 mA = 10 mA.

And the maximum current through load (when the zener is drawing minimum knee current) is 60 mA ý 5 mA = 55 mA.

Contributor: Naveen PN

03-02 — NEXT Q&A


For questions or comments about
Test Your EQ, e-mail eq@circuitcellar.com
.
Click here to get your listing up.

Copyright © 2003 ChipCenter-QuestLink
About ChipCenter-Questlink  Contact Us  Privacy Statement   Advertising Information  FAQ