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WHAT'S YOUR ENGINEERING QUOTIENT?

Problem 5—For a capacitor, i = Cędv/dt.
Let v = sin(węt); dv/dt = węcos(węt).
Now, Z = v/i, so for a capacitor, Z = sin(węt)/Cęwęcos(węt).
Z(C) = (1/węC)ętan(węt).
Please explain.

ANSWER

Problem 6—A transistor can be configured in three basic amplifier configurations: common-emitter, common-base, and common-collector. Each configuration can add power (gain) to a signal, but in different ways. Explain.

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