| Answer:
The answer is yes,
but only with the proper "light" and diode-semiconductor material
combination. Recall
that one may view light as consisting of energy packets or photons, and
the energy of each packet is a function of the wavelength
of light. A handy equation is E=1,240 /l
where the wavelength of light in nanometers (10-9 meters) and
E is the photon energy. When a photon is absorbed in a pn junction
and it has more energy than the bandgap energy of the semiconductor material,
it generates an electron. The bandgap energy of Germanium is 0.66 eV,
making these diodes sensitive to visible light and infrared light up to
1,880 nm Many diodes are made of silicon (1.122 eV) and these diodes
are sensitive to visible and infrared light up to 1,106 nm GaAs (1.424
eV) diodes are sensitive up to 900 nm.
Table 1 summarizes
the characteristics of common materials used in the manufacture of LEDs,
and as expected, the wavelength decreases as the bandgap energy increases.
If one illuminates a red LED with blue light, then the red LED will behave
as a photodiode. However, if we turn things around, and illuminate the
blue LED with the red light, it will not generate currentthe energy
of the red photons are too small to generate electrons in the SiC material.
|
Color
|
Material
|
Bandgap
|
|
Blue
|
SiC
|
2.64
eV
|
|
Green
|
Gap
|
2.19
eV
|
|
Yellow
|
GaP85As15
|
2.11
eV
|
|
Orange
|
GaP65As35
|
2.03
eV
|
|
Red
|
GaP4As6
|
1.91
eV
|
Table 1 - Characteristics
of Common Materials Used for LEDs
Thus, under the proper
conditions can sometimes use ordinary diodes and LEDs as photodiodes,
but practically, they perform poorly. A small-signal diode, even if it
enclosed in glass, is not optimized for light-current conversionthe
doping profile, exposure to light, reflections, etc. is simply wrong.
LEDs may seem be a better option, but are normally enclosed in colored
plastic that filters out much of the light.
|